How do you solve $6x - 45= - 5( x - 2)$ ?

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Answer 1 · 2017-06-07T13:02:24

$x=5$

The first step is to distribute $-5(x-2)$ .
Which is $-5x+10$ .
Now we have this:

$6x-45=-5x+10$

To solve this you add $5x$ to both sides, the $5x$ on the right cancels out.

$6x+5x-45=10$

Then you add $45$ to both sides the $45$ on the left cancels out.

$11x=10+45$

Now you are left with:

$11x=55$

Divide both by sides by $11$ and you get:

$x=5$

How do you solve 6x - 45= - 5( x - 2)6x - 45= - 5( x - 2)?