Question #8b7e5

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Answer 1 · 2017-06-09T00:16:18

$a=3$

We begin the problem by distributing the $3$ and $4$ into the parenthesis:

$6a+9-12a+24=15$

Combine like terms:

$-6a+33=15$

Subtract $33$ from both sides:

$-6a+cancel33-cancel33=15-33$

You are left with:

$-6a=-18$

Divide both sides by $-6$ :

$(-6a)/-6=(-18)/-6$

Our final answer is:

$a=3$

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