$P(E)=.24$ and $P(F)=.3$ . What is $P(E uu F)$ ?

Question

2154 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-10T02:38:41

The probability of P or F occurring is .468

The formula is:

$P(AuuB)=P(A)+P(B)-P(AnnB)$

Basically you take the probability of $E +F$ minus the probability of both events happening.

In terms of $(EuuF)$ :

$P(EuuF)=P(E)+P(F)-P(EnnF)$

Plug in the values:

$P(EuuF)=P(.24)+P(.3)-P(.24xx.3)$

$P(EuuF)=.24+.3-(.072)$

$P(EuuF)=.54-.072$

$P(EuuF)=.468$

P(E)=.24P(E)=.24 and P(F)=.3P(F)=.3. What is P(E uu F)P(E uu F)?