How do you solve $x(x-6)=72$ ?

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Answer 1 · 2017-06-10T17:52:19

$x=-6,12$

The first step is to distribute $x(x-6)$ :

$x^2-6x$

Now you have:

$x^2-6x=72$

Subtract 72 from both sides:

$x^2-6x-72=cancel72-cancel72$

$x^2-6x-72=0$

Factor it:

$(x-12)(x+6)=0$

Set each of them equal to zero and solve:

$x-12=0$

$x+6=0$

The answer is:

$x=-6,12$

How do you solve x(x-6)=72x(x-6)=72?