Question

Question #393ba

Answer 1

Use `y"-intercept"` and `x"-intercept"` or any two points on the line.

Explanation:

Looking at the equation, it is apparent that it would follow a linear model as there are no exponents or powers (eg `x^2`)

Then what we can do if find to points on the graph and draw a line through these points. The easiest points to find are usually the `y"-intercept"` and `x"-intercept"`

The `y"-intercept"` is when `x=0`, so to find that point, make `x=0` in the equation, and solve for `y`

`x=0`

`=>-2(0)+y=2`

`=>y=2`

Hence, when `x=0`, `y=2`. This represents the point `(0,2)`. So we should plot this point:


Then we calculate the other point, the `x"-intercept"`

The `x"-intercept"` is when `y=0`, so to find that point, make `y=0` in the equation, and solve for `x`

`y=0`

`=>-2x+(0)=2`

`=>-2x=2`

`=>x=2/-2`

`=>x=-1`

Hence, when `y=0`, `x=-1`. This represents the point `(-1,0)`. So we should plot this point with the other point:


Now join the two points with a straight line:


And you have the graph of your equation

You can use any two poinst on the line though. The only difference is that instead of finding when `x=0` or `y=0`, you would find when `x="another number like "3` or when `y="another number like "4`

It is easier to find the `y"-intercept"` and `x"-intercept"` but if you want to challenge yourself, find two points other than the `y"-intercept"` and `x"-intercept"`