How do you solve $4(x-2)=5$ ?

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Answer 1 · 2017-06-12T13:10:16

See a solution process below:

Step 1) Divide each side of the equation by $color(red)(4)$ to eliminate the need for parenthesis while keeping the equation balanced:

$(4(x - 2))/color(red)(4) = 5/color(red)(4)$

$(color(red)(cancel(color(black)(4)))(x - 2))/cancel(color(red)(4)) = 5/4$

$x - 2 = 5/4$

Step 2) Add $color(red)(2)$ to each side of the equation to solve for $x$ while keeping the equation balanced:

$x - 2 + color(red)(2) = 5/4 + color(red)(2)$

$x - 0 = 5/4 + (4/4 xx color(red)(2))$

$x = 5/4 + 8/4$

$x = 13/4$

Answer 2 · 2017-06-12T13:11:35

$x = 13/4$

Divide both sides by 4 to get

$x-2 = 5/4$

Add $2$ to both sides to get

$x = 5/4 +2$

Calculate and get

$x = 13/4$

How do you solve 4(x-2)=54(x-2)=5?