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What is the GCF of $(27 x)$ $(27x)$ and $(9 x^{2})$ $(9x^2)$ ?

1 Answer

Jun 13, 2017

$9 x$ $9x$

Explanation:

The GCF is $9 x$ $9x$ because we can divide both $27 x$ $27x$ and $9 x^{2}$ $9x^2$ by $9 x$ $9x$ .

$\frac{27 x}{9 x} = 3$ $(27x)/(9x)=3$

$\frac{9 x^{2}}{9 x} = x$ $(9x^2)/(9x)=x$

This is what is happening:

$(27color(blue)cancelx)/(9color(blue)cancel(x))=3$

$(color(blue)(cancel(9x))xxx)/color(blue)cancel(9x)=x$

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