Question #30ce8

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Answer 1 · 2017-06-15T00:52:53

$14w^2-21wx-10wy-8w+15xy+12x$

We want to distribute to $(2w-3x)(-4+7w-5y)$
What we can do is break up the first term : $color(blue)((2w-3x))$

$color(blue)((2w))(-4+7w-5y)$

$color(blue)((-3x))(-4+7w-5y)$

Now we can distribute and get our answer:

$color(blue)((2w))(-4+7w-5y)=-8w+14w^2-10wy$

$color(blue)((-3x))(-4+7w-5y)=12x-21wx+15xy$

We now have:

$-8w+14w^2-10wy+12x-21wx+15xy$

What we can do now is rearrange them:

$14w^2-21wx-10wy-8w+15xy+12x$

I think what made it trick was that there's three variables involved.

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