Question #583f8

2 Answers
Jun 15, 2017

I think you need to pay #$28.40#

Explanation:

You need to pay:
#$20.00# for the first #250g#
then you need to pay:
#3xx$2.80=$8.40#
to add
#3xx250g=750g#

(if you try only #2xx250g=500g# you are short of #50g# in the total and I do not think they are going to let it pass!)

giving a total of:

#$20.00+$8.40=$28.40#

to reach a total weight of:

#750+250=1000g#

that is #200g# more than you have to send but....

Jun 15, 2017

#$26.16#

Explanation:

Let's break down the information given:

We are given:

The cost for the first #250"g"# given to be #$20.00#

The cost for every additional #250"g"# to be #$2.80#

We want to find:

I'm the cost for the postage when it weighs #800"g"#

We can write the following equation:

#"C"=2.80a+20#

In this equation, #a# represents the cost for the additional #250"g"# added to the postage. We initially start with #250"g"# with no or #0# additional weight #250"g"# so to determine the cost of the postage we substitute in #0# for #a#:

#"C" = 2.80(0)+20#

#"C"=20# (In dollars)

This makes sense because we were given that the first #250"g"# with nothing extra is set at #$20.00#

Yet there is still something missing. We don't exactly know what #a# Is. We defined #a# to be the additional cost per #250"g"# added to our initial package of the same weight.

We can however, come up with this equation:

#550=250a#

Here #550# is the weight of the package remaining that we have yet to pay for because #800-250=550# since the first #250"g"# is already covered .
#250# represents the additional weight multiplied by #a# which tells us how many more per #250"g"# we need to pay for.

We then solve for #a#

#550/250=cancel(250/250)a#

#2.2=a#

Thus, we have an additional postage rate of #2.2# per #250"g"# to pay for.

Lastly we need to find the cost. Recall the first equation and now we can plug in #a# to find the final cost #"C"#

#"C"=2.80(2.2)+20#

#"C" = 26.16# (In dollars)

So if the package weighs #800"g"# the postage will cost you #$26.16# to send.