How do you find the derivative of $f (x) = 1 - 2 x^{2}$ $f(x)=1-2x^2$ ?

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Answer 1 · 2017-06-16T22:06:24

$\frac{d}{d x} = - 4 x$ $d/dx=-4x$

We find the derivative using the power rule:

$\frac{d}{d x} x^{n} = n x^{n - 1}$ $d/dxx^n=nx^(n-1)$

Simply to put it into words bring down the exponent and multiply it by the n (n in our case is equal to $2$ $2$ ) and subtract 1 from the exponent.

The derivative of a constant is always zero:

$\frac{d}{d x} c = 0$ $d/dxc=0$

Knowing this we can now move forward:

$f'(x)=d/dx1-d/dx2x^2$

$f'(x)=0-2(2)x^(2-1)$

$f'(x)=-4x$

How do you find the derivative of f(x)=1-2x^2f(x)=1−2x2f(x)=1-2x^2?