How do you factor $4s^2-26st+81t^2$ using the perfect squares formula?

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Answer 1 · 2017-06-17T04:50:07

$y = 4s^2 - 26st + 81t^2$
To be considered as a perfect square, y must be:
$y = 4s^2 - 36st + 81t^2 = (2s + 9t)^2$ .
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How do you factor 4s^2-26st+81t^24s^2-26st+81t^2 using the perfect squares formula?