Question #71d2a
2 Answers
Jun 17, 2017
See a solution process below:
Explanation:
First, rewrite the third term as:
We can now factor and
We can now factor the quadratic as:
Or
Jun 17, 2017
#x^2(a-b)-6x(a-b)-(-9)(a-b)# , taking -1 common from the last bracket.
=#x^2(a-b)-6x(a-b)+9(a+b)#
Taking (a-b) common from the whole expression we get
#(a-b)(x^2 -6x+9)#
So, the expression can be factorised as
#x^2(a-b)-6x(a-b)-9(b-a)=(a-b)(x-3)^2#
Hope this helps.
Feel free to comment if you want further explanation of any step.