Question

How do you differentiate `e^(2x^2+x)` using the chain rule?

Answer 1

`d/dx=e^(2x^2+x)(4x+1)`

Explanation:

The derivative of `e^x` is itself.
When you differentiate `e^x` you take the derivative of `x` basically you take the derivative of whatever `x` may be.

`d/dx=e^(2x^2+x)=e^(2x^2+x)`

Then take the derivative of what's inside:

`d/dx(2x^2+1)=4x+1`

Now you multiply them:

`d/dx=e^(2x^2+x)(4x+1)`

`d/dx=4e^(2x^2+x)x+e^(2x^2+x)`

Put you can simply leave it as:

`d/dx=e^(2x^2+x)(4x+1)`