How do you simplify $sqrt(8-x^2)$ ?

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Answer 1 · 2017-06-18T01:11:13

$2sqrt2-x$

To simplify $sqrt(8-x^2)$ you can approach it as:

$sqrt(8$ $&$ $sqrt(-x^2)$

Since this isn't a perfect $sqrt(8$ you can break it down into:

$sqrt(4)xxsqrt(2)$

Since $sqrt(4)$ is a perfect square we now get $2$
But we cannot break down $sqrt(2)$ any further so we leave it how it is.
This is what we got now:

$2sqrt2$

As for $sqrt(-x^2)$ it can be rewritten as:

$(-x^cancel2)^(cancel(1/2))=-x$

$(-x^2)^(1/2)=-x^(2/2)=-x$

So our final answer is $2sqrt2-x$

How do you simplify sqrt(8-x^2)sqrt(8-x^2)?