Question

How do you solve `\frac { 1} { 3} ( 3y + 3) - \frac { 3} { 8} = \frac { 3} { 4} y`?

Answer 1

`y=-5/2`

Explanation:

`1/3(3y+3)-3/8=3/4y`
Distribute `1/3` to `(3y+3)`.
`y+1-3/8=3/4y`
[Left Side] Combine the constants `1` and `-3/8`. Multiply `1` by `8/8` to give both constants the same denominator.
`y+(1*8/8)-3/8=3/4y`
`y+8/8-3/8=3/4y`
You can now evaluate `8/8-3/8`.
`y+5/8=3/4y`
Multiply the equation by `8` to cancel out the fractions.
`8(y+5/8=3/4y)`
`8y+5=6y`
Move all variables to one side and all constants to the other side and solve.
`2y=-5`
`y=-5/2`