Question #f7eed

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Answer 1 · 2017-06-19T21:37:01

The possible values of a are 0 and 1. See below for an explanation!

1. Set f(x) equal to 2.

$2 - x^2 + x^3 = 2$

2. Subtract 2 from both sides.

$- x^2 + x^3 = 0$

Commutative property:

$x^3 - x^2= 0$

3. Factor and solve.

$x^2(x - 1) = 0$

$x^2 = 0$
$sqrt(x^2) = +-sqrt(0)$
$color(red)(x = 0)$

$x-1 = 0$
$color(red)(x=1)$

Therefore, a could equal 0 or 1.