How do you evaluate the function $f (x) = - \frac{2}{3} x^{2} - x + 5$ $f(x)=-2/3x^2-x+5$ for f(6)?

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Answer 1 · 2017-06-19T22:00:50

The answer is -25. See below for an explanation.

To find f(6), simply plug in 6 for x and solve.

$f (6) = - \frac{2}{3} (6^{2}) - 6 + 5$ $f(6) = -2/3(6^2) - 6 + 5$

$= - 24 - 6 + 5$ $= -24 - 6 + 5$

$= - 25$ $= - 25$

How do you evaluate the function f(x)=-2/3x^2-x+5f(x)=−23x2−x+5f(x)=-2/3x^2-x+5 for f(6)?