How do you factor #6x^2 + 10#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Aiku Jun 20, 2017 #2(3x^2 + 5)# Explanation: Find a common factor between #6x^2# and #10# #2*3x^2 = 6x^2# #2*5 = 10# #2# Put #2# outside the brackets while dividing inside the brackets by the common factor #2# #(6x^2)/2 = 3x^2# #10/2 = 5# #2(3x^2 + 5)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 3667 views around the world You can reuse this answer Creative Commons License