If gas at 25.0 °C occupies 360 liters at a pressure of 100 kPa, what will be its volume at a pressure of 2.5O kPa?

Question

2792 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-20T23:27:20

14,400 L

Use the formula $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/(T_1) = (P_2V_2)/(T_2)$

(where P = pressure, V = volume, and T = temperature in Kelvin)

1. Plug the known values into the formula.

Don't forget to convert 25.0 °C to 298 K (273 + 25).

$\frac{100 \cdot 360}{298}$ $(100 * 360)/298$ = $\frac{2.5 \cdot x}{298}$ $(2.5 * x)/298$

2. Since temperature stays constant, we can eliminate the 298 K from the equation!

$(100 * 360)/cancel(298)$ = $(2.5 * x)/cancel(298)$

3. Solve for x.

$36000 = 2.5x$
$14400 = x$

Your final answer is 14,400 L.