How do you solve $8( w + 6) = 2w + 12$ ?

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Answer 1 · 2017-06-21T00:11:05

$w=-6$

First you distribute the left:

$8(w+6)=8w+48$

This is what we got so far:

$8w+48=2w+12$

What you do now is subtract $2w$ from both sides:

$8w-2w+48=cancel2w-cancel2w+12$

$6w+48=12$

Now subtract $48$ from both sides:

$6w+cancel48-cancel48=12-48$

$6w=-36$

Now divide both sides by $6$

$(cancel6w)/cancel6=-36/6$

$w=-6$

How do you solve 8( w + 6) = 2w + 128( w + 6) = 2w + 12?