If $h (x) = x - 7 and g (x) = x^{2}$ $h(x) = x-7 and g(x) = x^2$ , what is $(g \cdot h) (5)$ $(g*h)(5)$ ?

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Answer 1 · 2017-06-21T04:36:13

Because the domain of h and g is the set of real numbers their product can be defined.

Hence

$h (x) \cdot g (x) = (h \cdot g) (x) = (x - 7) \cdot x^{2}$ $h(x)*g(x)=(h*g)(x)=(x-7)*x^2$

Hence

$(h \cdot g) (5) = (5 - 7) \cdot 5^{2} = - 50$ $(h*g)(5)=(5-7)*5^2=-50$

If h(x)=x−7andg(x)=x2h(x) = x-7 and g(x) = x^2, what is (g⋅h)(5)(g*h)(5)?