How do you factor $- 4 x^{2} + 5 x - 12$ $-4x^2+5x-12$ ?

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How do you factor $- 4 x^{2} + 5 x - 12$ $-4x^2+5x-12$ ?

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Answer 1 · 2017-06-23T03:34:47

can't be factored.

Explanation:

$D = b^{2} - 4 a c = 25 - 192 = - 167 < 0$ $D = b^2 - 4ac = 25 - 192 = - 167 < 0$
This trinomial can't be factored because D < 0 and D isn't a perfect square.

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How do you factor $- 4 x^{2} + 5 x - 12$ $-4x^2+5x-12$ ?

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How do you factor $- 4 x^{2} + 5 x - 12$ $-4x^2+5x-12$ ?