How do you find the amplitude and period of y=2sec(4/5theta)?

1 Answer
Jun 24, 2017

Amplitude is 2.
Period is (5pi)/2 or 7.85398163.

Explanation:

Standard Form: y=asecb(x-c)+d
Equation: y=2sec(4/5theta)
a=2
b=4/5
c=none
d=none

AMPLITUDE
amplitude = distance from middle of graph (y=0) to highest and lowest points on graph
formula: |a|
|2|
2
Amplitude is 2.

PERIOD
period = interval in which the graph repeats itself
formula: (2pi)/|b|
(2pi)/|4/5|
(2pi)/(4/5)
2pi-:4/5
2pi*5/4
(10pi)/4
(5pi)/2 = 7.85398163
Period is (5pi)/2 or 7.85398163.