How do you find the amplitude and period of y=2sec(45θ)?

1 Answer
Jun 24, 2017

Amplitude is 2.
Period is 5π2 or 7.85398163.

Explanation:

Standard Form: y=asecb(xc)+d
Equation: y=2sec(45θ)
a=2
b=45
c=none
d=none

AMPLITUDE
amplitude = distance from middle of graph (y=0) to highest and lowest points on graph
formula: |a|
|2|
2
Amplitude is 2.

PERIOD
period = interval in which the graph repeats itself
formula: 2π|b|
2π45
2π45
2π÷45
2π54
10π4
5π2=7.85398163
Period is 5π2 or 7.85398163.