What is the slope of the line of this equation: $9 x + 8 y - 13 = 0$ $9x + 8y -13 =0$ ?

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Answer 1 · 2017-06-24T07:31:29

$m = - \frac{9}{8}$ $m=-9/8$

The slope of a line can be found when a linear equation is written in the form:

$y = m x + b$ $y = mx + b$

Where $m$ $m$ is the slope of the line.

You can get to this form, by algebraically isolating the $y$ $y$ .

$9 x + 8 y - 13 = 0$ $9x+8y-13=0$

Add $13$ $13$ to both sides:

$9 x + 8 y = 13$ $9x+8y=13$

Subtract $9 x$ $9x$ from both sides:

$8 y = - 9 x + 13$ $8y=-9x+13" "$ (notice the $9 x$ $9x$ can go in front of $13$ $13$ )

Divide both sides by $8$ $8$ :

$y = - \frac{9}{8} x + \frac{13}{8}$ $y=-9/8x+13/8$

The slope is the coefficient of the $x$ $x$ term.

ANSWER: $m = - \frac{9}{8}$ $m=-9/8$

Answer 2 · 2017-06-24T07:36:01

Slope = $- \frac{9}{8}$ $-9/8$

The equation of a straight line in slope $(m)$ $(m)$ and intercept $(c)$ $(c)$ form is: $y = m x + c$ $y=mx+c$

in this example: $9 x + 8 y - 13 = 0$ $9x+8y-13=0$ can be written as:

$y = - \frac{9}{8} x + \frac{13}{8}$ $y= -9/8x+13/8$

Hence the slope of $y$ $y$ is $- \frac{9}{8}$ $-9/8$ and the $y -$ $y-$ intercept is $\frac{13}{8}$ $13/8$

The graph of $y$ $y$ is shown below:
graph{9x+8y-13=0 [-10, 10, -5, 5]}

What is the slope of the line of this equation: 9x + 8y -13 =09x+8y−13=09x + 8y -13 =0?