How do you solve $- 3 (3 s - 4) - 12 = - 3 (7 s + 4) - 5$ $-3( 3s - 4) - 12= - 3( 7s + 4) - 5$ ?

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Answer 1 · 2017-06-25T02:20:59

$- \frac{17}{12}$ $-17/12$

First, distribute all the terms on the outside:

$- 9 s + 12 - 12 = - 21 s - 12 - 5$ $-9s+12-12=-21s-12-5$

Combine the constants:

$- 9 s = - 21 s - 17$ $-9s=-21s-17$

Move $- 21 s$ $-21s$ to the other side:

$12 s = - 17$ $12s=-17$

Divide both sides by $12$ $12$ :

$s = - \frac{17}{12}$ $s=-17/12$

How do you solve −3(3s−4)−12=−3(7s+4)−5-3( 3s - 4) - 12= - 3( 7s + 4) - 5?