How do you solve #-3( 3s - 4) - 12= - 3( 7s + 4) - 5#?

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Answer 1 · 2017-06-25T02:20:59

#-17/12#

First, distribute all the terms on the outside:

#-9s+12-12=-21s-12-5#

Combine the constants:

#-9s=-21s-17#

Move #-21s# to the other side:

#12s=-17#

Divide both sides by #12#:

#s=-17/12#