How do you simplify #(u + 7v ) ^ { 2} #?

1 Answer
Jun 26, 2017

#u^2+14uv+49v^2#

Explanation:

#(color(blue)(u)color(darkred)(+7v))(color(red)(u)color(green)(+7v))#

You proceed to FOIL it:

Where you multiply the #color(blue)"first term"# with the #color(red)"outer term"# then you multiply the #color(blue)"first term"# with the #color(green)"inner term"#:

#(color(blue)(u))(color(red)(u))=u^2#

#(color(blue)(u))(color(green)(7v))=7uv#

Now you multiply the #color(darkred)"last term"# with the #color(red)"outer term"# then you multiply the #color(darkred)"last term"# with the #color(green)"inner term"#:

#color(darkred)((7v))(color(red)(u))=7uv#

#color(darkred)((7v))(color(green)(7v))=49v^2#

Now combine them:

#u^2+7uv+7uv+49v^2#

Simplify:

#u^2+14uv+49v^2#