How do you solve ${(x - 9)}^{2} - 5 = 16$ $(x - 9) ^ { 2} - 5= 16$ ?

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Answer 1 · 2017-06-27T16:56:38

See below.

Let's rewrite the equation:

$(x - 9) (x - 9) - 5 = 16$ $(x-9)(x-9)-5=16$

$x^{2} - 9 x - 9 x + 81 - 5 = 16$ $x^2-9x-9x+81-5=16$

$x^{2} - 18 x + 76 = 16$ $x^2-18x+76=16$

$x^{2} - 18 x + 60 = 0$ $x^2-18x+60=0$

Now use the quadratic formula to solve for the roots.

How do you solve (x−9)2−5=16(x - 9) ^ { 2} - 5= 16?