How do you find #w(t^2)# given #w(t)=t^2-5 #?

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Answer 1 · 2017-06-28T15:38:14

#w(t^2)=t^4-5#

If the question was find #w(3)#, we would replace #t# with 3 and compute:

#w(3)=3^2-5#

#w(3)=9-5#

#w(3)=4#

In this case, let's replace #t# with #t^2#:

#w(t^2)=(t^2)^2-5#

Using the exponential law:

#(a^m)^n=a^(mn)#

#w(t^2)=t^4-5#