What is the slope of the line perpendicular to #2x-5y=3#?

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Answer 1 · 2017-06-29T06:55:18

The slope is #-5/2#

The slope of the line perpendicular to a given line is

#m'=-1/m#

where #m# is the slope of the known line.

The slope of a line in the standard form

#ax+by+c=0#

is #m=-a/b#

then, for the given line in the standard form

#2x-5y-3=0#

the slope is

#m=-2/-5=2/5#

and its perpendicular's slope is

#m'=-5/2#