Question

How do you find the value of the discriminant and state the type of solutions given `-9b^2=-8b+8`?

Answer 1

.

Explanation:

If `ax^2+bx+c=0`
Then discriminant`=` `b^2-4(a)(c)`
If discriminant`>0`, then solutions are two different real roots
If discriminant `=0`, then solutions are two equal real roots
If discriminant`<0`, then there are no real roots for solutions

In your case,
`-9b^2=-8b+8`
`9b^2-8b+8=0`

Discriminant
`=(-8)^2-4(9)(8)`
`=64-288`
`=-224`

So the type of the solution is ...
There are no real roots.