How do you solve #3y - 4\leq - 10#?

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Answer 1 · 2017-07-01T15:49:38

See a solution process below:

First, add #color(red)(4)# to each side of the inequality to isolate the #y# term while keeping the inequality balanced:

#3y - 4 + color(red)(4) <= -10 + color(red)(4)#

#3y - 0 <= -6#

#3y <= -6#

Now, divide each side of the inequality by #color(red)(3)# to solve for #y# while keeping the inequality balanced:

#(3y)/color(red)(3) <= -6/color(red)(3)#

#(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) <= -2#

#y <= -2#