How do you solve #3x + 4( x - 2) = 5x + 6#?

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Answer 1 · 2017-07-01T15:50:16

#x=7#

Use the distributive property on the #4(x-2)# term:

#3x+4x-8=5x+6#

#7x-8=5x+6#

Let's get the #x# terms on one side of the equation and the constant terms on the other.

Let's first subtract #5x# from both sides of the equation:

#2x-8=6#

Now, let's add 8 to both sides of the equation:

#2x=14#

Finally, let's dive both sides of the equation by #2# to find #x#:

#x=7#