How do you solve #\frac { 5} { 6} - \frac { m } { 3} = \frac { 1} { 9}#?

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Answer 1 · 2017-07-04T20:58:53

#m=13/6#

Get common denominator #(18)# to give:
#15/18 - (6m)/18 = 2/18#

You can then clear the #18# to give:

# 15-6m = 2#

Rearrange and solve to give the answer above

Answer 2 · 2017-07-04T20:59:49

#m = 13/6#

If you have an equation which has fractions, you can get rid of the denominators by multiplying by the LCM of the denominators.

#5/6 -m/3 = 1/9" "larr# In this case the LCD is #18#

#(18xx5)/6 -(18xxm)/3 = (18xx1)/9" "larr#multiply each term by #18#

#(cancel18^3xx5)/cancel6 -(cancel18^6xxm)/cancel3 = (cancel18^2xx1)/cancel9 "larr# cancel the denominators

#15-6m = 2#

#15-2 = 6m#

#13= 6m#

#m = 13/6#