How do you solve this system of equation using the elimination method: $2x + 4y = 16, 2x - 4y = 0$ ?

Question

1682 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-04T22:37:16

See below.

We notice that there is a $+4y$ and a $-4y$ . If we added the two equations, we would eliminate $y$ .

$2x+4y=16$
$+$
$2x-4y=0$

$4x=16$

$x=4$

Plugging this in,

$2(4)+4y=16$

$4y=8$

$y=2$

Thus, our solution set is $(4,2)$

How do you solve this system of equation using the elimination method: 2x + 4y = 16, 2x - 4y = 02x + 4y = 16, 2x - 4y = 0?