How do you multiply #(x^(2) + 9)(x+4)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer eduarchitect Jul 5, 2017 #x^3 + 4x^2+9x+36# Explanation: just multiply internal factors #(x^2.x) +( x^2 .4)+(9.x)+(9.4)# = #x^3 + 4x^2+9x+36# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1396 views around the world You can reuse this answer Creative Commons License