Question #8470b

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Answer 1 · 2017-07-06T13:05:25

$8 N H_{3} + 3 C l_{2} \to N_{2} + 6 N H_{4} C l$ $8NH_3 + 3Cl_2 -> N_2 + 6NH_4 Cl$

$N H_{3} + C l_{2} \to N_{2} + N H_{4} C l$ $NH_3 + Cl_2 -> N_2 + NH_4 Cl$

Ammonia $N H_{3}$ $NH_3$ react with Chlorine gas $C l_{2}$ $Cl_2$ to produce nitrogen $N_{2}$ $N_2$ and Ammonium chloride $N H_{4} C l$ $NH_4 Cl$ .

$8 N H_{3} + 3 C l_{2} \to N_{2} + 6 N H_{4} C l$ $8NH_3 + 3Cl_2 -> N_2 + 6NH_4 Cl$ $\to$ $->$ Balanced

The Balanced equation represents the combustion of Ammonia in Chlorine atmosphere.

Balancing Equation: You have to find the values to key in behind the compound to make both products and reactants equal..

As in H in the product side must be equal with H in the reactant sides

The rule affects all element in the equation..