How do you solve #8x = 4( 6x + 20)#?

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Answer 1 · 2017-07-06T17:27:50

#x = -5#

1. Distribute the 4 to everything inside the parentheses.

#8x = 4(6x + 20)#
#8x = 24x + 80#

2. Subtract 24x from both sides to get the variable on one side only.

#8x - 24x = cancel(color(red)(24x)) + 80 cancel(color(red)(- 24x))#

#-16x = 80#

3. Divide both sides by -16 to isolate x.

#(-16x)/(-16) = 80/(-16)#

#x = -5#

That's your answer!