How do you solve the following linear system: $3x-y=23 , y+8x=11$ ?

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Answer 1 · 2017-07-07T00:15:04

See below.

Notice the coefficients of the $y$ term. It seems that adding is the simplest way to solve this.

$3x-y=23$
$+$
$8x+y=11$

$11x=34$

$x=34/11$

Plugging this in,

$3(34/11)-y=23$

$102/11-y=253/11$

$y=-151/11$

Thus, our solution is $(34/11,-151/11)$

How do you solve the following linear system: 3x-y=23 , y+8x=11 3x-y=23 , y+8x=11 ?