Question

How do you find the x and y intercepts of `8y=-2x+20`?

Answer 1

`x`-intercept: `(10,0)`
`y`-intercept: `(0,5/2)`

Explanation:

First, isolate the `y` variable by dividing `8` on both sides.
`y=-2/8x+20/8`
`y=-1/4x+5/2`

To find the `x`-intercept, substitute `0` in for `y` and solve for `x`.
`0=-1/4x+5/2`
`-5/2=-1/4x` ---> multiply by the reciprocal, `-4`, on both sides
`x=20/2=10`

To find the `y`-intercept, substitute `0` in for `x` and solve for `y`.
`y=-1/4(0)+5/2`
`y=0+5/2=5/2`

Finally, write the intercepts as coordinates on a graph.
`x`-intercept: `(10,0)`
`y`-intercept: `(0,5/2)`

I hope this helps a lot! :)