Question #c843a

2 Answers
Jul 10, 2017

v=25ms^-1

Explanation:

m=1500kg
v_(0)=15ms^-1
F_1=1000N
t=15s

Before a force acting on it, the object is at constant velocity (assuming no other forces is acting on it: eg. friction), thus
NetF=0

After a force acting on it, the object experiences a net force of same magnitude as the applied force.
F=ma
1000=1500a
a=2/3 ms^-2

v=v_0+at
v=15+2/3*15
v=15+10
v=25ms^-1

Jul 10, 2017

Its velocity will be 25m/s

Explanation:

We can use two known equations to solve this problem.
These are
F=m*a
v=u +a*t

Lets substitute the values
F=1000N
m=1500 kg
then we have a=F/m=1000/1500 =2/3 m/s^2

Also
u=15 m/s
t=15 s
so that v=u+a*t=15 + 2/3*15=15+10=25s