Question

How do you solve `1/(n-8)-1=7/(n-8)` and check for extraneous solutions?

Answer 1

`n=2`

Explanation:

`1/(n-8)-1=7/(n-8)`

Subtracting `1/(n-8)` from both sides,

`-1=6/(n-8)`

`8-n=6`

`n=2`

This solution works, as we notice that `n=8` is the only extraneous value, but is not an actual solution (as it makes the denominator 0).