Question

How do you completely factor `x ^ { 6} - 18x ^ { 5} + 81x ^ { 4}`?

Answer 1

`x^4(x-9)^2`

Explanation:

If you take `x^4` out as the initial factor, you're left with:

`x^4(x^2-18x+81)`

This quadratic can further be factorised to:

`(x-9)(x-9)` which gives the answer above.