Question

How do you solve `8- 5r = - 2`?

Answer 1

See a solution process below:

Explanation:

First, subtract `color(red)(8)` from each side of the equation to isolate the `r` term while keeping the equation balanced:

`-color(red)(8) + 8 - 5r = -color(red)(8) - 2`

`0 - 5r = -10`

`-5r = -10`

Now, divide each side of the equation by `color(red)(-5)` to solve for `r` while keeping the equation balanced:

`(-5r)/color(red)(-5) = (-10)/color(red)(-5)`

`(color(red)(cancel(color(black)(-5)))r)/cancel(color(red)(-5)) = 2`

`r = 2`

Answer 2

1. Unknowns one side, knowns another.
   8+2=5r (the signs will change when the numbers are transferred to the another side of the = sign)

2. Do the addition, subtraction, multiplication, division etc. procedures

6=5r

1. To get the unknown on one side divide both sides with the number that multiplies the unknown. (NOTE THAT it does NOT apply if there is + or - operation such as: 3=5+7r)

6=5r /5
`6/5=(5r)/5`

1. Do the rest of operations.

`6/5=r`
`r=6/5`