How do you differentiate #f(x)=3sqrt(tan4x^2)# using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Καδήρ Κ. Jul 18, 2017 #f'(x)=(12x)/(cos^2 4x^2 sqrt(tan4x^2))# Explanation: #f'(x)=3/(2sqrt(tan4x^2))*(tan4x^2)'=# #3/(2sqrt(tan4x^2))*1/(cos^2 4x^2)(4x^2)'=# #3/(2sqrt(tan4x^2))*1/(cos^2 4x^2)*8x=# #(12x)/(cos^2 4x^2 sqrt(tan4x^2))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1631 views around the world You can reuse this answer Creative Commons License