Question

Question #cfe7e

Answer 1

The range is 1000 metres and time of flight is 14.14 seconds.

Explanation:

So mainly I am considering the angle of elevation; I think it's `45^o` not 450.

The Range is maximum at `theta` = `45^o`.

`:.` `R=(u^2 sin(2theta))/(g)` `=` `(u^2)/(g)`

By substituting the values `u=1000m//s`, `theta=45^o` we get,

`R=1000m`.

while time of flight `T=(sqrt(2)u)/(g)` `=` `10sqrt(2)` seconds or `T=14.14s`.