Question #cfe7e

1 Answer
SaiGanesh Gotetti · Nathan L.
Jul 19, 2017

The range is 1000 metres and time of flight is 14.14 seconds.

Explanation:

So mainly I am considering the angle of elevation; I think it's #45^o# not 450.

The Range is maximum at #theta# = #45^o#.

#:.##R=(u^2 sin(2theta))/(g)##=##(u^2)/(g)#

By substituting the values #u=1000m//s#, #theta=45^o# we get,

#R=1000m#.

while time of flight #T=(sqrt(2)u)/(g)##=##10sqrt(2)# seconds or #T=14.14s#.

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