How do you solve abs(2y+7)=7|2y+7|=7?

1 Answer
Jul 20, 2017

As the absolute value of 2y+7=72y+7=7, then 2y+7=+-72y+7=±7, as abs(), takes the magnitude of the number, whether its positive or negative, abs(), makes it positive.

So, either 2y+7=72y+7=7, or 2y+7=-72y+7=7

Let's solve 2y+7=72y+7=7 first:
We take 7 from both sides first- 2y+7-color(red)(7)=7-color(red)(7)-=2y=02y+77=772y=0

Then we divide both sides by 2 - (2y)/color(red)(2)=0/color(red)(2)-=y=02y2=02y=0

Now, let's solve for 2y+7=-72y+7=7:
We take 7 from both sides first- 2y+7-color(red)(7)=-7-color(red)(7)-=2y=-142y+77=772y=14

Then we divide both sides by 2 - (2y)/color(red)(2)=-14/color(red)(2)-=y=-72y2=142y=7