A particle of mass 100 g is fired with velocity of 20 m/s making angle 30° with horizontal. When it reaches highest point, what is the magnitude of change in momentum?

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Answer 1 · 2017-07-21T02:01:07

1 $kg$ $ms^-1$

Initial velocity $= vCos30i + vSin30j$

Final velocity $= vCos30i$

Change in momentum = $m*$ (Final velocity- Initial velocity)

$Δp$ = $0.1kg* [vCos30i - (vCos30i - vSin30j)]$

$Δp = 0.1kg * (-vSin30j)$

$Δp = 0.1kg * (-20ms^-1 × 1/2)j$

$Δp = -0.1kg × 10ms^-1j$

$Δp = -1 kg*ms^-1 j$

Magnitude of change in momentum is 1 kg $ms^-1$