How do you solve the system of equations $y = \frac{2}{7} x - 9$ $y= \frac { 2} { 7} x - 9$ and $y = \frac{7}{2} x + 8$ $y = \frac { 7} { 2} x + 8$ ?

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How do you solve the system of equations $y = \frac{2}{7} x - 9$ $y= \frac { 2} { 7} x - 9$ and $y = \frac{7}{2} x + 8$ $y = \frac { 7} { 2} x + 8$ ?

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Answer 1 · 2017-07-21T04:35:28

There are many methods to use; but I would suggest to use substitution because you do not have to move the equations to their standard form.

Explanation:

Since both of the equations are equal to y, we can infer that they are the same and solve for x, and then plug in the x-value for the y-value. And you know it's going to have one solution because they are both linear.

$\frac{2}{7} x - 9 = \frac{7}{2} x + 8$ $2/7x-9 = 7/2x+8$

$- \frac{45}{14} x = 17$ $-45/14x=17$

$x = - \frac{238}{45}$ $x=-238/45$

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How do you solve the system of equations $y = \frac{2}{7} x - 9$ $y= \frac { 2} { 7} x - 9$ and $y = \frac{7}{2} x + 8$ $y = \frac { 7} { 2} x + 8$ ?