How do you divide #\frac { 8y ^ { 2} - 6y - 3} { 2y - 1}#?
2 Answers
Jul 22, 2017
Explanation:
I had to use algebraic division for this one:
Jul 22, 2017
Explanation:
#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(4y)(2y-1)color(magenta)(+4y)-6y-3#
#=color(red)(4y)(2y-1)color(red)(-1)(2y-1)color(magenta)(-1)-3#
#=color(red)(4y)(2y-1)color(red)(-1)(2y-1)-4#
#"quotient "=color(red)(4y-1)," remainder "=-4#
#rArr(8y^2-6y-3)/(2y-1)=4y-1-4/(2y-1)#