How do you simplify $\frac { 2b a ^ { 4} \cdot ( - 2a b ^ { 4} ) ^ { 2} } { - 2a ^ { 2} }$ ?

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Answer 1 · 2017-07-23T06:23:03

$-4a^4b^9$

$(2ba^4*(-2ab^4)^2)/(-2a^2)$

First, we square the factor in brackets.

A] $=> (-2ab^4)^2=4a^2b^8$

Now we multiply the factors in the numerator.

B] $2ba^4*4a^2b^8=8a^6b^9$

The equation now looks like:

$(8a^6b^9)/(-2a^2)$

We now expand the terms in the numerator and denominator and cancel the common ones.

$(2*4*a*a*a*a*a*a*b^9)/(-2*a*a)$

$(1cancel2*4*cancela*cancela*a*a*a*a*b^9)/(-1cancel2*cancela*cancela)$

$-4a^4b^9$

How do you simplify \frac { 2b a ^ { 4} \cdot ( - 2a b ^ { 4} ) ^ { 2} } { - 2a ^ { 2} }\frac { 2b a ^ { 4} \cdot ( - 2a b ^ { 4} ) ^ { 2} } { - 2a ^ { 2} }?